fixed a bug, parser can now parse numbers that contains zeros

expressions.txt

-x+2/5223+y+44+4+2^12/222
+x+2/40+3*x
\ No newline at end of file

src/Parser.java

@@ -101,6 +101,9 @@ public class Parser {
         if(ts.size()==1) {
             return null;
         }
+        if(parseCharacter(ts.get(1).getData(), ".")) {
+            return null;
+        }
         BinaryOperation operation;
         if(ts.get(1).getType()!= Lexer.TokenType.SPECIAL) {
             throw new ParserException("SyntaxError: unexpected operator: " + ts.get(1).getData());
@@ -151,7 +154,7 @@ public class Parser {
         if (ts.size()>1) {
             //if the next token is of TokenType.SPECIAL, check if it's a comma
             //if it is, create a decimal
-            if(ts.get(0).getType() == Lexer.TokenType.SPECIAL) {
+            if(ts.get(1).getType() == Lexer.TokenType.SPECIAL) {
                 if(parseComma(ts)) {
                     value = parseDecimal(ts);
                 }
@@ -191,8 +194,8 @@ public class Parser {
             return new Number(data);
         }
 
-        parseDigitWithoutZero(data);
-        parseDigit(data);
+        parseDigitWithoutZero(data.substring(0,1));
+        parseDigit(data.substring(1));
         return new Number(data);
     }
 
@@ -219,9 +222,9 @@ public class Parser {
     }
 
     private Boolean parseComma(List<Lexer.Token> ts) throws ParserException {
-        String data = ts.get(0).getData();
+        String data = ts.get(1).getData();
         if(parseCharacter(data, ".")) {
-            if(ts.get(1).getType()!= Lexer.TokenType.NUMBER) {
+            if(ts.get(2).getType()!= Lexer.TokenType.NUMBER) {
                 throw new ParserException("SyntaxError: no number after comma");
             }
             return true;